KIMIYYA PRO TV

 There are so many ways of solving a word problems, depending on the types of the problems given. One of such ways is by using semulteneous equation.       Today we are going to solve a linear problem involving semulteneous e EXAMPLE: To solve such kind of question. Firstly we need to convert the statement into an equations. Now we can generate an equations using the above given information as below :  So, let us use equation 1 and 2 semultineously to find the value of x and y. Using an elimination method we can still create another two equations from equation one and two above: By doing so we have obtained another two equations as below: By solving equation three and four above semultineously we will have: Then the value of x will be: Now, to find the value of y, we have to substitute the above value of x  in to anyone of the above four equations. Since we have the values of x and y, this means that: Hence: Now we can easily find the cost of 7 apples and 1...

HOW TO FIND THE EQUATION OF A CIRCLE.      In this question, we have been given the coordinate of the center of the circle and the radius of that circle ( i.e the distances from any point at the circumference of the circle to the center of that circle). And we have been ask to find the equation of that circle.      We have so many methods of solving such kind of problems, but we are now going to use the standard equation of the circle. Since now we have the standard equation of the circle as given above, so we have to find the value of g, f, c and then subtitute them.   But we have to remember that also: So this means that: To find the value of we have to remember the relationship below: Then let substitute the values of r,g and f in the above relationship,so that we will find the value of c by making it to be the subject of the relation. Now we have the values of g,f and c. Hence we have to substitute them in the standard equation of the circle above....

SOLVING A RADICAL EQUATION WITH UNLIKE ROOT. Hello everyone!          In this class we are going to learn how to solve a radical equation. Radical equation are the same, and today we are going to solve one them.    Normally, in solving a radical equation we are trying to take one of the radical term to other side and then isolate the other term. Typically we are going to take the cube root of both side, and that is going to be massive.               So, here we are going to apply another method which is going be a substitution method.            Now we have this equation in a single variable, for the time being Iam going to turn it in to more variables.           The first thing Iam going to do is that to replace the first radical with m and the second radical with n . So that the whole equation will change into  m + n = 1 Now from there i can get more equati...

SOLVING AN EXPONENTIAL EQUATIONS           Hello my freinds. Wellcome back to our new class. Today we are going to learn how to solve an exponential equation in two variable. We have diffrent method of solving an exponential equations, the method is determined defending on the nature of the given equation.       EXAMPLE :         If six power x plus six power y is the same as fourty two and x plus y is the same as 3, then find the value of x and y? Image 1  SOLUTION:          In this given question we have been given two equations with two unknown, so we can solve them simulteneously using subtitution method.         Firstly we can let the first equation to be equal to equation one, and the second equation to be equal to equation two. However,we used equation two to find equation three by making y to be the subject of the formula from it. Image 2    ...

HOW TO SOLVE A CLASSIC ALGEBRAIC EQUATION . Hello !   Sometime, in algebraic eqtiotions it is not always about solving for x or y. We have to solve for the whole equation, and today we are going to solve one equation of such kind of problem.       Supposed, we have been given an equation: Fourteen x minus three y divide by x plus four y is equal to 4 and ask to find the result of x minus two y. A classic algebraic equation. In this problem we can let the first given equation be equation one and the second given expression to be two, for the simplicity of the work. From that, we can simplify the first equation, by multiplying  each side by the denominator ( i.e x + y).  And then, collect the like term, so that all the terms with x will be on one and all the terms with y will be on the otherside of rhe equation. Therefore, we can let one of x or y to be the subject of the formula. So that, we will subtitute it in equation 2 given above. After we found th...

HOW TO SOLVE THIS KIND OF QUESTION IN A SIMPLEST WAY.  Firstly, the question is to be pronounce as "intergration of two ex multiply by open bracket ex restpower two plus 1 closed bracket rest power 50 with respect to the derivative of ex.           There are so many process/ ways of solving this kind of questions, but the most simplest method is by using subtitution method.          Let u be the whole function that are inside the bracket and then we have U = X^2 + 1   du/dx = 2x Make dx to be the subject of the formulae, we will have dx = du/2x Subtitute them in the original question, we will have:   The integral of 2x ( u ) du/2x Then we have : 2x in the numerator functions and 2x in the denominator functions, so they will cancelled each other. Then we will have :        The integral of u power 50 dx  So, integral of udu = u power 50+1 divide by 50+1 then + the constant c     ...